Python实现随机生成有效手机号码及身份证功能示例

import os
import random
import datetime
BASE_DIR = os.path.dirname(os.path.dirname(__file__))
DC_PATH = BASE_DIR + "districtcode.txt"
# 随机生成手机号码
def createPhone():
 prelist=["130","131","132","133","134","135","136","137","138","139","147","150","151","152","153","155","156","157","158","159","186","187","188"]
 return random.choice(prelist)+"".join(random.choice("0123456789") for i in range(8))
# 随机生成身份证号
def getdistrictcode(): 
 with open(DC_PATH) as file: 
  data = file.read() 
  districtlist = data.split('\n') 
 for node in districtlist: 
 #print node 
  if node[10:11] != ' ': 
   state = node[10:].strip() 
  if node[10:11]==' 'and node[12:13]!=' ': 
   city = node[12:].strip() 
  if node[10:11] == ' 'and node[12:13]==' ': 
   district = node[14:].strip() 
   code = node[0:6] 
   codelist.append({"state":state,"city":city,"district":district,"code":code})
def gennerator(): 
 global codelist 
 codelist = [] 
 if not codelist:
  getdistrictcode()
 id = codelist[random.randint(0,len(codelist))]['code'] #地区项 
 id = id + str(random.randint(1930,2013)) #年份项 
 da = datetime.date.today()+datetime.timedelta(days=random.randint(1,366)) #月份和日期项 
 id = id + da.strftime('%m%d') 
 id = id+ str(random.randint(100,300))#，顺序号简单处理 
 i = 0
 count = 0
 weight = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2] #权重项 
 checkcode ={'0':'1','1':'0','2':'X','3':'9','4':'8','5':'7','6':'6','7':'5','8':'5','9':'3','10':'2'} #校验码映射 
 for i in range(0,len(id)): 
  count = count +int(id[i])*weight[i] 
  id = id + checkcode[str(count%11)] #算出校验码 
  return id
print createPhone()
print gennerator()