Python中shape计算矩阵的方法示例

> from numpy import *
> import operator
> a =mat([[1,2,3],[5,6,9]])
> a
matrix([[1, 2, 3],
    [5, 6, 9]])

> shape(a)
(2, 3)
> a.shape[0] #计算行数
2
> a.shape[1] #计算列数
3

Examples
--------
> np.shape(np.eye(3))
(3, 3)
> np.shape([[1, 2]])
(1, 2)
> np.shape([0])
(1,)
> np.shape(0)
()
> a = np.array([(1, 2), (3, 4)], dtype=[('x', 'i4'), ('y', 'i4')])
> np.shape(a)
(2,)
> a.shape
(2,)