Python获取央视节目单的实现代码
(编辑:jimmy 日期: 2024/11/18 浏览:3 次 )
本文实例讲述了Python获取央视节目单的方法。分享给大家供大家参考。具体如下:
#! /usr/bin/python # -*- coding: utf-8 -*- import urllib,re,unicodedata,string,sys from time import strftime,localtime channel={"1":"CCTV-1","2":"CCTV-2","3":"CCTV-3","4":"CCTV-4亚洲", "5":"CCTV-4欧洲","6":"CCTV-4美洲","7":"CCTV-5","8":"CCTV-6", "9":"CCTV-7","10":"CCTV-8","11":"CCTV-9","12":"CCTV-10", "13":"CCTV-11","14":"CCTV-12","15":"CCTV新闻","16":"CCTV少儿", "17":"CCTV音乐","18":"CCTV_E","19":"CCTV-F","20":"CCTV-高清"} if __name__=="__main__": print "@@" print "@@ 你可以在命令行后输入数字(1-20)来选择频道 " print "@@ 通过在命令行后键入help获取频道列表" print "@@" if len(sys.argv)==1: Select="8" else: if sys.argv[1]=="help": for i in range(len(channel)): print "%3d : %11s" % (i+1, channel["%s" % (i+1)]), if(i%4 == 3): print "" sys.exit(0) if string.atoi(sys.argv[1])>20 or string.atoi(sys.argv[1])<=0: print "Out of Range. Please Select 1-20." sys.exit(0) else: Select=sys.argv[1] print '正在获取节目单,请稍后...' date=strftime('%Y%m%d',localtime()) response = urllib.urlopen("http://tv.cctv.com/soushi/28/0"+Select+"/"+date+".shtml") Result=response.read() #list=re.findall(r"<div class='tlb_right'><div class='l'>(.+",Result,re.S) list=re.findall(r"上午节目(.+",Result,re.S) list2=re.findall(r"<li>(.+",list[0],re.S) morning=[] afternoon=[] listnum=0 for i in range(len(list2)): i=re.sub('<.+?>','',list2[i]) if string.atoi(i[:2])>=12: #将上午的节目于下午的节目分开 afternoon.append(i) else: morning.append(i) if len(morning)>len(afternoon): listnum=len(morning) else: listnum=len(afternoon) print "-"*80, print " "*13+"上午节目"+" "*26+"下午节目" print " "*14+"========"+" "*26+"========" for i in range(listnum): if(i<len(morning)): print "%-4s %-29s" %(morning[i][:5],morning[i][5:]), else: print " "*35, if(i<len(afternoon)): print "%-4s %-30s" %(afternoon[i][:5],afternoon[i][5:]) else: print " "*37 print "-"*80, print " "*24,strftime("%Y年%m月%d日"), print "%s 节目单" %channel[Select]
希望本文所述对大家的Python程序设计有所帮助。
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